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doubts in c

sudarsan_amar Posted: Thu Jul 10, 2003 7:51 pm

Joined: 10 Jul 2003

Posts: 2

doubts in c

sir,
       i am sudarsan completed my B.E(CSE) in 2003 just recently.
i am searching for jobs. iam sending some questions in c.please reply to this questions.
                                                                         with regards ,
                                                                          sudarsan.
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kishorehelp Posted: Thu Jul 10, 2003 8:37 pm

Joined: 10 Jul 2003

Posts: 1

doubts in c

hello friends
this is kishore,i am sending link to get all previous papers

anirban.bravepages.com/ppapers.html

bye
kishore, can be believed for ever

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tvmanikandan Posted: Fri Jul 11, 2003 10:12 am

Joined: 18 Jul 2003

Posts: 2

doubts in c

I have worked in G++ in Unix.

#include<stdio.h>
#define cube(x)(x*x*x)
main()
{
int i=3;j;
j=cube(i++);
printf("%d%d",i,j)
}

what will be the o/p : 4 27

main()
{
int *i,j=7;
i=(int*)malloc(sizeof(++j));
printf("%d",j);
}
what will be the o/p : 7

I don`t get the reason behind the outputs

______________________________ Reply Separator _________________________________
Subject: [Programmers-Town] doubts in c
Author: sudarsan.amar (sudarsan_amar@...) at internet
Date: 7/10/03 8:21 PM

#include<stdio.h>
#define cube(x)(x*x*x)
main()
{
int i=3;j;
j=cube(i++);
printf("%d%d",i,j)
}
what will be the o/p?
main()
{
int *i,j=7;
i=(int*)malloc(sizeof(++j));
printf("%d",j);
}
what will be the o/p?

c_mallircr Posted: Fri Jul 11, 2003 3:07 pm

Joined: 11 Jul 2003

Posts: 2

doubts in c

Hi, if u compile this program with -E option, i.e., gcc -E <this file name> u will see the pre-processor expansion like this. main() { int i=3, j;
j = (i++ * i++ * i++); // Here the increment operator won`t incremnt for each i++ after completing this statement it will increment by thrice. So i will be 3 + 3 after this statement. j = 3 * 3 * 3;
printf("%d%d", i,,j);} Rgds,
Malli
--- tv.manikandan@... wrote: --------------------------------- I have worked in G++ in Unix. #include<stdio.h> #define cube(x)(x*x*x) main() { int i=3;j; j=cube(i++); printf("%d%d",i,j) } what will be the o/p : 4 27 main() { int *i,j=7; i=(int*)malloc(sizeof(++j)); printf("%d",j); } what will be the o/p : 7 I don`t get the reason behind the outputs ______________________________ Reply Separator _________________________________ Subject: [Programmers-Town] doubts in c Author: sudarsan.amar (sudarsan_amar@...) at internet Date: 7/10/03 8:21 PM #include<stdio.h> #define cube(x)(x*x*x) main() { int i=3;j; j=cube(i++); printf("%d%d",i,j) } what will be the o/p? main() { int *i,j=7; i=(int*)malloc(sizeof(++j)); printf("%d",j); } what will be the o/p?
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sudarsan_amar Posted: Fri Jul 11, 2003 6:31 pm

Joined: 10 Jul 2003

Posts: 2

doubts in c

sorry your output is wrong for first question.tv.manikandan@... wrote:
I have worked in G++ in Unix. #include<stdio.h> #define cube(x)(x*x*x) main() { int i=3;j; j=cube(i++); printf("%d%d",i,j) } what will be the o/p : 4 27 main() { int *i,j=7; i=(int*)malloc(sizeof(++j)); printf("%d",j); } what will be the o/p : 7I don`t get the reason behind the
outputs______________________________ Reply Separator _________________________________Subject: [Programmers-Town] doubts in cAuthor: sudarsan.amar (sudarsan_amar@...) at internetDate: 7/10/03 8:21 PM#include<stdio.h>#define cube(x)(x*x*x)main(){int i=3;j;j=cube(i++);printf("%d%d",i,j)}what will be the o/p?main(){int *i,j=7;i=(int*)malloc(sizeof(++j));printf("%d",j);}what will be the o/p?To unsubscribe from this group, send an email to:Programmers-Town-unsubscribe@yahoogroups.comYour use of Yahoo! Groups is subject to the Yahoo! Terms of Service.
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amitsoni29 Posted: Sat Jul 26, 2003 3:22 pm

Joined: 26 Jul 2003

Posts: 1

doubts in c

--- In Programmers-Town@yahoogroups.com, tv.manikandan@s... wrote:
> I have worked in G++ in Unix.
>
> #include<stdio.h>
> #define cube(x)(x*x*x)
> main()
> {
> int i=3;j;
> j=cube(i++);
> printf("%d%d",i,j)
> }
>
> what will be the o/p : 4 27
For these type of questions, Dennis Ritchie says that these are very
much compiler depended and hence are not the logical questions to be
asked. These type of programs have no standard output and may produce
different results on different platforms.

--
Amit.

>
> main()
> {
> int *i,j=7;
> i=(int*)malloc(sizeof(++j));
> printf("%d",j);
> }
> what will be the o/p : 7
>
> I don`t get the reason behind the outputs
>
>
>
>
>
> ______________________________ Reply Separator
_________________________________
> Subject: [Programmers-Town] doubts in c
> Author: sudarsan.amar (sudarsan_amar@y...) at internet
> Date: 7/10/03 8:21 PM
>
>
> #include<stdio.h>
> #define cube(x)(x*x*x)
> main()
> {
> int i=3;j;
> j=cube(i++);
> printf("%d%d",i,j)
> }
> what will be the o/p?
> main()
> {
> int *i,j=7;
> i=(int*)malloc(sizeof(++j));
> printf("%d",j);
> }
> what will be the o/p?

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