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Array Decays2Pointer
Joined: 17 Jul 2003
Posts: 2
Array Decays2Pointer
Hello All,
char a[6] = "abcd";
char *p = "abcd";
->I understood that name of an array is a CONSTANT, which means that
char a[6]; which means that if if were to read a[3], compiler goes to the start of the object named "a" and increments 3 spaces to reach at a[3]
->in case of p[3], compiler goes to the object pointed to by "p", and increments by 3 to reach at p[3].
This is what i learnt from http://www.eskimo.com/~scs/C-faq/q6.2.html
Except for the point that an array name cannot be changed and will always have to point to the start of object a unlike "p" which could be point to any other object which essentially means a[3] DOES`NT necessarily have to be p[3].Is there anything else?
But then why does http://www.eskimo.com/~scs/C-faq/q6.3.html say that, QUOTED:
"The exceptions are when the array is the operand of a sizeof or & operator, or is a string literal initializer for a character array."
array in the case of string literal DOESn`t decay into an array???????
Sorry about the long mail, had to make the point clear where i didn`t understand....
thanks all
Kitta
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