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(Query): Need Answers
Joined: 22 Dec 2004
Posts: 2
(Query): Need Answers
1)Whats the diff between
// What it will do ?
-- for(;;);
// Next
-- func()
-- {
-- func();
-- }
what kind of output we can get ?
2)
main()
{
int x =5, y;
y = size(++x);
printf("X = %d", x);
}
Prints X = 5 only Why ?
bye
Vikram
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Joined: 29 Dec 2004
Posts: 2
(Query): Need Answers
> 1)Whats the diff between
> // What it will do ?
> -- for(;;);
>
> // Next
> -- func()
> -- {
> -- func();
> -- }
Ans:
Both will go in Infinite Loop
> what kind of output we can get ?
>
> 2)
> main()
> {
> int x =5, y;
> y = size(++x);
> printf("X = %d", x);
> }
> Prints X = 5 only Why ?
>
Ans:
I am not sure,, but what i think is may be sizeof
operator will take datatype of the variable during
calculation not the value, so may be before
calculating it may come to know about data type.
My reasoning may be incorrect, if wrong let me correct
myself
Bye
> bye
> Vikram
>
>
>
> __________________________________
> Do you Yahoo!?
> Jazz up your holiday email with celebrity designs.
> Learn more.
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Joined: 02 Jan 2005
Posts: 5
(Query): Need Answers
Hi,
pls correct me in case i am wrong
--- In Programmers-Town@yahoogroups.com, gururaj bo <guru_bo@y...> wrote:
> > 2)
> > main()
> > {
> > int x =5, y;
> > y = size(++x);
> > printf("X = %d", x);
> > }
> > Prints X = 5 only Why ?
> >
> I am not sure,, but what i think is may be sizeof
> operator will take datatype of the variable during
> calculation not the value, so may be before
> calculating it may come to know about data type.
>
I think this is because when we pass an argument (by value) to a
function a copy of the argument is made and is passed to the function.
Since we are incrementing X while passing, it is the copy which gets
affected and not the original one. So in the next statement we are
getting the answer as 5.
Bye
Sumit Garg
Joined: 04 Jan 2005
Posts: 2
(Query): Need Answers
--- Sumit Garg <sg7650@...> wrote:
>
>
> Hi,
>
> pls correct me in case i am wrong
> --- In Programmers-Town@yahoogroups.com, gururaj bo
> <guru_bo@y...> wrote:
> > > 2)
> > > main()
> > > {
> > > int x =5, y;
> > > y = size(++x);
> > > printf("X = %d", x);
> > > }
> > > Prints X = 5 only Why ?
> > >
> > I am not sure,, but what i think is may be sizeof
> > operator will take datatype of the variable during
> > calculation not the value, so may be before
> > calculating it may come to know about data type.
> >
> I think this is because when we pass an argument (by
> value) to a
> function a copy of the argument is made and is
> passed to the function.
> Since we are incrementing X while passing, it is the
> copy which gets
> affected and not the original one. So in the next
> statement we are
> getting the answer as 5.
>
> Bye
> Sumit Garg
Hi,
My opinion the reason is related to concepts like Pre
increment and Post increment. Pls comment.
Regards
Kishor
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