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Re: Finding the set of consecutive integers which sum up to
Joined: 06 Jan 2005
Posts: 2
Re: Finding the set of consecutive integers which sum up to
1. Finding the set of consecutive integers which sum up to the max Suppose we have a list of integers .. say [1,3,0.-4,5,4,-6,0,8,-5] ... Now, in this list, the group (4,5) can be called the set of consecutive integers that sums up to the max total (i.e, 9). Now how do we write a program for this? I was thinking on the lines of starting from 1 and summing up things. Then starting from 3 and summing up things... This does not seem to be efficient...
Ans: Just take the first two nos. and store in two variables, add it up, and store in 3rd variable, next consider 2nd & 3rd nos. add then compare with stored value, if new no is greater update the storing variable by new no.along with the two added numbers, continue with the consecutive integers list and at the end the group and the total can be achieved.
for the 2nd question I didn`t get the image, sorry.
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Joined: 07 Jan 2005
Posts: 2
Re: Finding the set of consecutive integers which sum up to
hi,
herez the code
int a[]={-23,-19,222,-113,-4,15,-13,-12,-1117,-3,18}; // jus for ex : int i=0,index1=i++, max=a[i-1]+a[i]; for(;i<=9;i++) if(a[i]+a[i+1]>max) { index1=i; max=a[i]+a[i+1]; }cout<<"Position: "<<index1<<" and "<<index1+1; cout<<"
Values: "<<a[index1]<<" and "<<a[index1+1];
kindly intimate me if there is any problem with the code
thanx
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